View PDF Version PRE-LAB FOR EQUILIBRIUM LAB
PART I. TITRATION OF AN AMINO ACID USING A
pH METER
PART II. SPECTROPHOTOMETRIC STUDY OF AN INDICATOR
GOAL/PURPOSE:
NEEDED PRIOR CONCEPTS:
** the lab could be simplified/made
qualitative by eliminating the "unknown" acid aspect of determining the
molecular weight of the amino acid. This reduces the need for discussion
of pKa. Alternatively, this could
be done after a preliminary experiment in which a student determines, for
example, the Ka for acetic acid using indicators
(methyl red and bromcresol green work fairly well).
LABORATORY SKILLS:
PRE/POST -LAB ACTIVITIE:
SAFETY:
PROCEDURES:
Part I
1. The equivalence point is the point in a titration when enough titrant has been added to react completely with the substance being titrated.
2a.
Ka = [H+][CH3COO-] = _ (x)(x)_ = _ x2 _ = 1.8 x 10-5 x<<0.1002b.
[CH3COOH] 0.100-x 0.100x = 1.3 x 10-3 [H+] = 1.3 x 10-3 pH = -log(1.3 x 10-3) = 2.89
Ka = [H+][CH3COO-] = _ (x)(2.00 x 10-3/0.120 L) _ = 1.8 x 10-5
[CH3COOH] 0.010 - (2.00 x 10-3/0.120 L)x=7.2 x 10-5 M pH = -log(7.2 x 10-5) = 4.14
2c.
40.0 mL (0.100 mol/1000mL)=4.00 x 10-3
mol NaOH
0.010 mol CH3COOH
Ka= (x)(4.00 x 10-3/0.140 L) = 1.8 x 10-5
((0.010-4.00 x 10-3)/0.140 L)x=2.7 x 10-5 M pH= -log (2.7 x 10-5)=4.57
2d.
50.0 mL(0.100 mol/1000mL)=5.00 x 10-3
mol NaOH 0.010 mol CH3COOH
Ka= (x)(5.00 x 10-3/0.150 L) = 1.8 x 10-5
((0.010-5.00 x 10-3)/0.150 L)x=1.8 x 10-5 M pH=4.74
2e.
60.0 mL(0.100 mol/1000mL)=6.00 x 10-3
mol NaOH 0.010 mol CH3COOH
Ka= (x)(6.00 x 10-3/0.160 L) = 1.8 x 10-52f. Ka= (x)(9.90 x 10-3/0.199 L) = 1.8 x 10-5
((0.010-6.00 x 10-3)/0.160 L)x=1.2 x 10-5 M pH=4.92
x=1.8 x 10-7 M pH=6.74
2g. Equivalence point
Kb=Kw/Ka = 1.0 x 10-14/1.8 x 10-5 = 5.6 x 10-10 = [OH-][CH3COOH]/[ CH3COO-](X2)/(0.010 M - x)[=0.01] = 5.6 x 10-10
x = 2.4 x 10-6 pH=14.00-5.63 = 8.37 pOH = -log(2.4 x 10-6) = 5.63
2h. 101.0 mL(0.100 mol/1000
mL)=0.0101 mol NaOH
OH- from H2O will be negligible2i. 110.0(0.100 mol/1.0 L) = 0.011 mol NaOH0.0101 mol - 0.0100mol = 0.0001 mol OH- excess
[OH-] = 0.0001 mol/0.201 L = 5.0 x 10-4 M
pOH=3.3 pH=10.7
Again, OH- from H2O will be negligible3.0.0110 - 0.0100 mol = 0.001 mol OH- excess
[OH-] = 0.001 mol/0.210 L) = 4.8 x 10-3
pOH=2.32 pH=11.7
4. pH=8.37
5. pH=4.57
6. It changes color to let you know you are near the equivalence point.
7. They are weak acids or bases that change slightly and this alters their optical properties.
8. The pH of the equivalence point should fall in the range for the color change of an indicator.
9. The endpoint is where the indicator changes color. The equivalence point is where equal amounts of acid and base have been added. (With proper selection of indicators the error between the two will be small.)
Follow the directions for each question/section. Answer in the space provided.
1.Find a chart of the Electromagnetic Spectrum in your text. Look at all the labels given for the chart. What quantity (wavelength, energy, frequency, etc.) is increasing from left to right in this figure?
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2. Which type of light (electromagnetic radiation) is more damaging to your skin: ultraviolet or microwaves?
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Use your answer for Question #1 to explain why this is true. __________________________________________________
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3. List the colors in the visible spectrum from high energy to low energy. _________________________________________
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4. What types of light can be found in sunlight? ___________________________________________________________
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Questions #5-10 refer to the figure on the other side of this sheet.
5. Study the chart on the other side of this sheet. What quantity is
increasing from left to right on this chart?
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6. What, if anything would you have to do to the chart on the other side of this sheet to make it coincide with, or read the same
way as the figure in your textbook? ____________________________________________________________________
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7. Which type of light is more energetic, red or blue visible light?_______________________________________________
8. How is the energy of the light related to the wavelength? __________________________________________________
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9. Which of these figures, the one given here or the one in your textbook, matches or is similar to the spectrophotometric graph
you obtained in the lab? (If both are similar, indicate why you think so.) _________________________________________
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Questions 10-20 refer to the graph you printed out in the experiment.
10. Label the curves on the graph using A,B,C designations as well
as the actual color and pH of each solution.
Identify the pH range of acid solutions____________,
basic solutions____________, neutral solutions _____________ .
11. Identify the quantity plotted on the horizontal axis of your graph. ___________________________________________
Does it increase or decrease from left
to right?________________________________________________________
Write the names for the colors of the visible spectrum in the proper
region on the horizontal axis of the graph.
12. Explain the difference between the terms "absorbed" and "transmitted".
Use a dictionary if necessary.
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13. If the absorbance line goes up at a particular color region of the spectrum, what does that mean in terms of how the material
will look? (color it will appear to be). ___________________________________________________________________
14. If the bromthymol blue was visually blue, what region in the visible portion of the spectrum (color of light) is absorbed by the
solution? ________________________________________________________________________________________
15. If the bromthymol blue solution is visually yellow, what portion of the spectrum (color of light) is transmitted by the
solution? ________________________________________________________________________________________
16. What color is bromthymol blue in
(a) acid solution ______________17. Acid-base indicators, such as bromthymol blue, can be thought of as weak acids themselves, i.e. as molecules which gain or lose a H+(aq) in acid-base reactions. In acid solution there are lots of H+(aq) around and the molecule is in the form "HBb" (where Bb represents the rest of the bromthymol blue molecule other than the proton, H+, which is gained or lost.) In basic solution, the H+ is pulled off the molecule, and it is in the form Bb-. The reaction can be represented as:
(b) basic solution ______________
(c) neutral solution _____________
HBb <----> H+ + Bb-
color: _____________ colorless________________
Identify the color of each of the two forms of bromthymol blue by filling in the blanks above. (The double arrow indicates an "equilibrium" reaction. It can go either way, depending on the conditions.)
18. What is the color of bromthymol blue in neutral solution? ________________________________________________
Consult with other lab groups as needed. How do you account for
the color? Explain your answer fully.
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19. Suppose you made errors in using the pipette and pipette pump (e.g. disregarding the graduation marks and draining the pipette completely), thus adding more than 10 mL indicated on the pipette. How would this affect the color of your solution and the results graphed by the spectrophotometric trace? Explain your answer fully.
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20. Write a statement describing the relationship between pH and the concentration of a colored ion in solution.
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